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    SisLovesMe- Stepsister Lana Rhodes Caught Being a Stripper And Gets Fucked

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    9,393,612 views
    70% 26702 11337
    From:  - 115 videos  879,938
    Pornstars:  Lana Rhoades
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    Added on: 1 year ago
    Featured on: 1 year ago
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    All Comments (123)

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    1 year ago
    this ones old
    3 months ago
    i dont think so !
    1 year ago
    Latest update is here https://www.pornhub.com/view_video.php?viewkey=ph59f37eca8add0 & Sislovesme.com always has the newest update
    1 year ago
    the new sound when you like a comment is sooo creepy xD
    4 months ago
    What sound
    4 months ago
    4 months ago
    WTF!? THATS FUCCIN CREEPY?!?!
    1 year ago
    Really? Your just going to cut in an old video and try to tell us it's new
    4 months ago
    I can tell by her tits
    1 year ago
    I have not seen it before but you're right
    1 year ago
    Hey guys anyone here particularity good at maths? I have no idea about this question.... "Find a closed formula for summation(k=0 to m) floor(sqrt(k)) when m is a positive integer". I'd really appreciate advice on where to begin.
    8 months ago
    Thenks had the same question
    1 year ago
    f(p^2 +q) = (sum(k=1 to p-1) (p-k)(2p-2k+1)) + (q+1)p. Simplifying this and realising that for any m, m=g(m)^2 + (m-g(m)^2)), so p is our g(m) and q is m-g(m)^2, we can show that f(m)=-4/3 p^4 + 9p^3 - 115/6 p^2 + (31/2 + q)p -3.
    1 year ago
    For ease if writing I'll denote f(m) to be sum(k=0 to m) floor(sqrt(k)) and g(k) to be floor(sqrt(k)), and finally i for floor(sqrt(k)). Start by considering what outputs g gets when putting in various k. We notice that g(k)=p for p^2, p^2 +1,...,p^2 +2p, and that there are 2p+1 of these numbers. Next we calculate f(p^2), which ends up being p + sum(k=1 to p-1) (p-k)(2p-2k+1). What about f(p^2 +1)? We notice a pattern for f(p^2 +q) where q is between 0 and 2p;
    1 year ago
    She has those eyes like she's gonna r**e you in your sleep
    1 year ago
    nigga i wish

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