This is an adult website

This website contains age-restricted materials including nudity and explicit depictions of sexual activity. By entering, you affirm that you are at least 18 years of age or the age of majority in the jurisdiction you are accessing the website from and you consent to viewing sexually explicit content.

I am under 18 - Exit

Our parental controls page explains how you can easily
block access to this site.

© Pornhub.com, 2024

Video poster

Resume

Resolver 1

9.4K Views

89%

3 years ago

65

8

7

Added to your Favorites

Video Liked View liked videos Video Liked! Sign up to store more Liked Videos Sign up

Click here to see your liked videos

Login or Sign Up now to add this video!

Login or Sign Up now to add this video to stream!

Close

Jump to your favorite action

Close

falodurotti8

7 Videos 68 Subscribers

Categories

Amateur Old/Young (18+) School (18+) Teen (18+)

Suggest

Vote on categories

Amateur
Old/Young (18+)
School (18+)
Teen (18+)

Submit

Pornstars

Thank you for your suggestions! Our team is reviewing them!

Tags

teenager math

Suggest

Vote on tags

Teenager math

Submit

Production

homemade

Suggest

Vote on production

Professional
Homemade

Added on 3 years ago

View more

All Comments (6)

Login or Sign Up now to post a comment!

Cypooos

Cypooos

2 years ago

Great video, overall good reasonment, but I must say that on line 2, you forgot the square on the right side. And explaning the domain of x could help to explain why we can divide by x on both side (x different to 0)

7

MathMan1618

MathMan1618

1 year ago

No, he didn't forget the square. He forgot to square it. Furthermore, the domain of the RHS is not just as you say. If we assume we are working over the real numbers, which appears to be the case, then it is clear that our interval on which the function is defined is (infinity,-3sqrt(2+sqrt(6))) U (0,infinity). Technically you said nothing wrong about the domain, but it is more specific than you indicated.

1

Juliorodri67

Juliorodri67

2 years ago

Gran video, se me bajó la pitolina y me entraron ganas de hacer matrices, un saludo!!!!

3

MathMan1618

MathMan1618

1 year ago

Note: For the two comments below, it was not allowing me to use proper notation. When I say the set B=a1,a2,...an, I mean that a1, a2,...,an are distinct elements of the set B. Furthermore when I say Rx, I mean the polynomial ring R adjoin x. (Here x is the indeterminate.)

2

MathematikIstGut

MathematikIstGut

2 years ago

great video 🙂

2

MathMan1618

MathMan1618

1 year ago

(2) if and only if g(x)=d, so long as d is not a pole of f, that is, a zero of g. By the fundamental theorem of algebra, we are guaranteed that g has at most two complex solutions, and as stated earlier, these solutions form the set A, a proper subset of R. Even more specifically, notice that the set A is also a proper subset of Q.

0

[[dateAdd]]

[[commentMessage]]

0

© Pornhub.com, 2024